Design Formulas for Permanent-Magnet Bearings

[+] Author and Article Information
Brad Paden

Department of Mechanical and Environmental Engineering, University of California, Santa Barbara, CA 93106e-mail: paden@engineering.ucsb.edu

Nelson Groom

NASA LARC (ret.), P.O. Box 125, White Marsh, VA 23183e-mail: njgroom@visi.net

James F. Antaki

Biomedical Engineering, Carnegie Mellon University, Pittsburgh, PA 15213e-mail: antaki@andrew.cmu.edu

J. Mech. Des 125(4), 734-738 (Jan 22, 2004) (5 pages) doi:10.1115/1.1625402 History: Received March 01, 2003; Revised April 01, 2003; Online January 22, 2004
Copyright © 2003 by ASME
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Yonnet,  J. P., Lemarquand,  G., Hemmerlin,  S., and Olvierrulliere,  E., 1991, “Stacked Structures of Passive Magnetic Bearings,” J. Appl. Phys., 70(10), pp. 6633–6635.
Antaki,  J., Banda,  S., Paden,  B., and Piovoso,  M., 2002, “Award Winning Control Applications,” IEEE Control Syst. Mag., 22(6), December, pp. 8–20.
Baermann, M., 1956, German patent application B 30 042 dated 1954 (German specification 1071 871).
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Yonnet,  J. P., 1978, “Passive Magnetic Bearings With Permanent Magnets,” IEEE Trans. Magn., 14(5), pp. 803–805.
Yonnet,  J. P., 1981, “Permanent Magnet Bearings and Couplings,” IEEE Trans. Magn., 17(1), pp. 1169–1173.
Marinescu,  M., and Marinescu,  N., 1994, “A New Improved Method for Computation of Radial Stiffness in Permanent Magnet Bearings,” IEEE Trans. Magn., 30(5), pp. 3491–3494.
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Magnetic bearing geometry with load; (a) isometric view, (b) axial cross-section and, (c) radial cross-section
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An axially magnetized bearing has same load capacity and stiffness as the bearing in Fig. 1 (See 1)
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Geometry of interacting periodically magnetized plates showing direction of magnetization
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Magnetization pattern in the stacked structure of Fig. 1. Br is the remanence of the permanent magnet material, λ is the spatial period of the bearing pole pattern, and z is the displacement along the axis of the bearing.
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Radial peak force versus normalized gap for bearings of Figs. 1 and 2; d/λ=1/8,1/4,1/2,∞; Br=1.3 Tesla
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Radial restoring force versus displacement for bearings of Figs. 1 and 2; d/λ=1/2;g0/λ=0.1,0.22,0.5,1.0; Br=1.3 Tesla
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Radial stiffness as a function of nominal gap d/λ=1/2;Br=1.3 Tesla
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Axial force as a function of axial displacement for two values of the radial displacement x(d=λ/2,g=0.22λ,Br=1.3 Tesla)



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